CLEVELAND — Cleveland Browns linebacker Joe Schobert has been named AFC Defensive Player of the Week, the NFL announced on Wednesday. He’s the first Browns player to win AFC Defensive Player since linebacker D’Qwell Jackson was given the title in Week 12 of 2012.
During a 41-24 victory against Miami, Schobert recorded five tackles, two interceptions and four passes defensed. He became the sixth linebacker in NFL history to have at least two interceptions and four passes defensed.
He has led all AFC players with two interceptions and tied for the lead among AFC players with four passes defensed.
Schobert became the sixth linebacker in NFL history to have at least two interceptions in consecutive games.
Schobert joins Jamie Gillan and Nick Chubb as award winners this year. It’s the first time the Browns have won AFC Offensive, Defensive and Special Teams Player of the Week honors in the same season since 2010.
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