Former Cleveland Cavaliers forward Dean Wade has agreed to contract terms with the Philadelphia 76ers, according to ESPN's Shams Charania.
Negotiations were finalized Tuesday night for a four-year, $39 million deal, Charania reported.
Wade joined the Cavs as an undrafted free agent in 2019.
Wade was the first big offseason deal made by new 76ers president of basketball operations Gansey. Gansey joined the Cleveland Cavaliers in 2011 and worked as their general manager since 2022 before he left for Philadelphia and long championed Wade, who went undrafted in 2019 out of Kansas State.
The 6-foot-9 Wade spent his entire seven-year NBA career with the Cavaliers. He never has averaged more than 6.0 points in a season and is expected to become a key rotation player in Philadelphia.
The 29-year-old Wade has played 32 career playoff games.
Additionally, Charania reported that former Cavs guard Keon Ellis agreed to a two-year, $18 million contract with the Brooklyn Nets.
